AQA A-Level Physics: Paper 2

7408/2  ·  2 hours  ·  85 marks  ·  34% of A-Level  ·  Sections 6 – 8

Section 6.1 - Further mechanics: circular motion and SHM

6.1.1  Circular motion

An object moving in a circle at constant speed is accelerating because its direction continuously changes. The acceleration points towards the centre of the circle this is centripetal acceleration. Angles are measured in radians (2π rad = 360°). Note: the direction of angular velocity is not examined.

Angular velocity: ω = v/r = 2πf = 2π/T (unit: rad s-1) Linear speed: v = ωr Centripetal acceleration: a = v²/r = ω²r (directed towards centre; derivation not examined) Centripetal force: F = mv²/r = mω²r (directed towards centre)

The centripetal force is not a new type of force it is provided by an existing force: tension (in a string), gravity (for orbiting satellites), friction (for a car cornering), or the normal contact force.

The centripetal force does no work because it is always perpendicular to the velocity. Therefore, an object in circular motion at constant speed has constant kinetic energy only direction changes, not speed.

6.1.2 – 6.1.3  Simple harmonic motion (SHM)

SHM is defined by the condition: a ∝ −x (acceleration proportional to displacement, always directed towards equilibrium).

Defining equation: a = −ω²x Displacement: x = A cos(ωt) [or A sin(ωt), depending on start conditions] Velocity: v = ±ω√(A² − x²); maximum speed vmax = ωA at x = 0 Maximum acceleration = ω²A (at x = ±A) Total energy: E = ½mω²A² (constant) KE = ½mω²(A² − x²); PE = ½mω²x²

Graphical representations: the x–t graph is sinusoidal. The v–t graph is derived from the gradient of the x–t graph (v and x are 90° out of phase: v is maximum when x = 0 and vice versa). The a–t graph is derived from the gradient of the v–t graph (a is 180° out of phase with x). KE and PE both vary sinusoidally with time (at twice the frequency of oscillation); total energy is constant.


SHM systems:

Mass-spring system
T = 2π√(m/k). Period independent of amplitude. Increases with mass; decreases with stiffer spring (larger k). Works horizontally or vertically.
Simple pendulum
T = 2π√(L/g). Period independent of mass and amplitude (for small angles <~10°). Other harmonic oscillators (e.g. liquid in U-tube) may appear full information is provided in questions.

Required Practical 7: investigation into simple harmonic motion using a mass–spring system and a simple pendulum.

At maximum displacement (x = A): velocity = 0, acceleration = maximum (= ω²A), PE = maximum, KE = 0. At equilibrium (x = 0): velocity = maximum, acceleration = 0, PE = 0, KE = maximum. Total energy is constant throughout.

6.1.4  Forced vibrations and resonance

Free vibrations
Object oscillates at its natural frequency f0 after an initial displacement. No energy input after the start. Amplitude is constant (undamped) or decreasing (damped).
Forced vibrations
An oscillating external force drives the system at the driving frequency fd. The system oscillates at fd, not at f0.
Resonance
Occurs when fd = f0. Amplitude is maximum. Energy transferred to system most efficiently. Phase lag = π/2 (90°).
Damping
A resistive force reduces amplitude. Light damping: slow reduction, resonance peak still sharp. Heavy damping: fast reduction, resonance peak broad and low. Critical damping: returns to equilibrium in shortest possible time without oscillating.

Increased damping: lowers the resonance peak amplitude and broadens it; shifts the peak slightly below f0.

Resonance in stationary waves: resonance also occurs in mechanical systems producing stationary waves e.g. a vibrating string or air column resonates when the driving frequency matches a harmonic of the system's natural frequency. The same principles apply: maximum amplitude at resonance, damping reduces the sharpness of the peak.

Real-world examples of resonance: Tacoma Narrows bridge collapse (wind matching natural frequency); tuned strings and organ pipes (stationary wave resonance); microwave ovens (water molecule resonance). Damping is used to prevent unwanted resonance (car suspension, building earthquake protection).

Section 6.2 - Thermal physics

6.2.1  Thermal energy transfer

Internal energy
The sum of the randomly distributed kinetic and potential energies of all the particles in a system. Increasing temperature increases the mean KE of particles. Changing state changes PE (bonds) without changing temperature.
Absolute temperature
Measured in Kelvin (K). T(K) = T(°C) + 273 (more precisely +273.15). Absolute zero (0 K = −273.15 °C): minimum possible temperature; particles have minimum energy. Cannot be reached in practice.

First law of thermodynamics (qualitative): the internal energy of a system is increased when energy is transferred to it by heating or when work is done on it (and vice versa). Both routes are equivalent in their effect on internal energy.

Specific heat capacity: Q = mcΔθ c = specific heat capacity (J kg-1 K-1); Δθ = temperature change (K or °C) For continuous flow: power input = mcΔθ × (flow rate in kg s-1) e.g. if water flows at rate ṁ kg s-1: P = ṁcΔθ Specific latent heat: Q = ml l = specific latent heat (J kg-1) Latent heat of fusion (melting/solidifying) Latent heat of vaporisation (boiling/condensing)

During a change of state, temperature is constant even though energy is being supplied or removed. The energy changes the potential energy (intermolecular bonds) not the kinetic energy of the particles.

6.2.2  Ideal gases

The gas laws (Boyle's, Charles's, Pressure law) are experimental relationships between p, V, T and the mass of gas. The ideal gas equation combines them.

Ideal gas equation (two forms): pV = nRT (n = number of moles, R = 8.31 J mol-1 K-1) pV = NkT (N = number of molecules, k = 1.38×10-23 J K-1) Relationship: k = R / NA where NA = 6.02×1023 mol-1 Gas laws (fixed mass): Boyle's law: pV = constant (constant T) Charles's law: V/T = constant (constant p) Pressure law: p/T = constant (constant V) Combined: p1V1/T1 = p2V2/T2 Work done by a gas at constant pressure: W = pΔV Molar mass (g mol-1 or kg mol-1): mass of one mole of a substance. Molecular mass: mass of one molecule (in kg or u, where 1 u = 1.66×10-27 kg).

Assumptions of an ideal gas:

  • Large number of molecules in random motion
  • Volume of molecules negligible compared to the volume of the gas
  • Time of collisions negligible compared to time between collisions
  • Collisions are perfectly elastic (no energy lost)
  • No intermolecular forces except during collisions

Required Practical 8: investigation of Boyle's law (constant temperature) and Charles's law (constant pressure) for a gas.

Always use temperature in Kelvin in gas law calculations. A common error is substituting degrees Celsius. Absolute zero is defined as the temperature at which an ideal gas would have zero volume/pressure the concept of absolute zero comes from extrapolating gas law graphs.

6.2.3  Molecular kinetic theory

Brownian motion (e.g. smoke particles in air, pollen in water) provides direct evidence for the existence of atoms: the random, jerky motion of visible particles is caused by random collisions with invisible, fast-moving molecules.

The gas laws are empirical (derived from experiment). The kinetic theory model is theoretical, derived from applying Newton's laws and conservation of momentum to molecules bouncing off container walls. Together they explain why pV = ⅓Nmcrms².

Kinetic theory equation (derivation uses conservation of momentum): pV = ⅓ Nmcrms² where N = number of molecules, m = mass of one molecule, crms = root mean square speed Average molecular KE: ½mcrms² = (3/2)kT = (3/2)RT/NA Root mean square speed: crms = √⟨c²⟩

For an ideal gas, internal energy consists entirely of the kinetic energy of the molecules (there are no intermolecular potential energies). Hence internal energy ∝ T.

Our understanding of gas behaviour has developed over time: from early observations of gas laws (empirical), to Maxwell and Boltzmann's statistical mechanics, building a deeper theoretical foundation that connected temperature to molecular motion.

The mean KE depends only on temperature, not on the type of gas. At the same temperature, all ideal gas molecules have the same mean translational KE regardless of their mass. Heavier molecules move slower (lower rms speed) to have the same KE.

Section 7 (part) - Gravitational and electric fields

7.1  Fields

A force field is a region in which a body experiences a non-contact force. Force fields can be represented as vectors (the direction must be determined by inspection of the field).

Force fields arise from:

  • Interaction of mass → gravitational fields
  • Interaction of static charge → electrostatic fields
  • Interaction between moving charges → magnetic fields
Similarities (gravity & electrostatics)
Both obey inverse-square laws. Both use field lines and the concept of potential. Both have equipotential surfaces. Force equations have the same mathematical form (compare F = Gm₁m₂/r² with F = Q₁Q₂/(4πε₀r²)).
Differences (gravity & electrostatics)
Masses always attract. Charges may attract or repel (opposite charges attract; like charges repel). Gravitational potential is always negative; electric potential can be positive or negative.

7.2  Gravitational fields

A gravitational field is a region where a mass experiences a force. Field lines point towards the attracting mass (gravity is always attractive).

Newton's law of gravitation (universal attractive force between all matter): F = Gm1m2 / r² (G = 6.67×10-11 N m² kg-2) Gravitational field strength (force per unit mass): g = F/m = GM/r² (unit: N kg-1 or m s-2) Gravitational potential (zero at infinity; negative for attractive field): Vg = −GM/r (unit: J kg-1) Work done moving mass m through potential difference ΔV: ΔW = mΔV Gravitational potential energy: Ep = mVg = −GMm/r

Equipotential surfaces are surfaces of constant potential. No work is done moving a mass along an equipotential surface. Equipotentials are perpendicular to field lines.

Field strength and potential: g = −ΔV/Δr (g = negative gradient of V–r graph). The change in potential ΔV between two points equals the area under the g–r graph between those points.


Orbits: for a circular orbit, gravitational force provides centripetal force:

GMm/r² = mv²/r → v = √(GM/r) Period: T = 2πr/v → T² = 4π²r³/GM (Kepler's Third Law: T² ∝ r³) Satellite total energy (circular orbit): KE = GMm/(2r); GPE = −GMm/r; Total E = −GMm/(2r) (always negative: bound) Raising an orbit requires adding energy (KE decreases, GPE increases more). Escape velocity (KE = |GPE| at surface): vesc = √(2GM/r) ≈ 11.2 km s-1 from Earth's surface
Geostationary orbit
T = 24 h. Orbital radius ≈ 42 000 km from Earth’s centre (altitude ≈ 36 000 km above surface). Equatorial plane, west→east. Appears stationary from Earth. Used for communications and weather satellites.
Low Earth orbit (LEO)
Altitude 200–2000 km. Short period (~90 min). Lower cost to reach; used for GPS satellites, ISS, Earth observation. Not stationary relative to Earth’s surface.

Gravitational potential is always negative (zero at infinity). The closer to the mass, the more negative the potential. Work must be done to move a mass away from an attracting body. Escape velocity follows from setting KE = |GPE| at the surface.

7.3  Electric fields

An electric field is a region where a charged particle experiences a force. Field lines run from positive to negative charges.

Coulomb's law (force between point charges in a vacuum; air treated as vacuum): F = Q1Q2 / (4πε0r²) ε0 = 8.85×10-12 F m-1 (permittivity of free space) For a charged sphere, the charge may be treated as if concentrated at its centre. Electric field strength (force per unit positive charge): E = F/Q (unit: N C-1 or V m-1) Radial field (point charge): E = Q / (4πε0r²) Uniform field (parallel plates): E = V/d (derived from work done: Fd = QΔV) Electric potential (zero at infinity): V = Q / (4πε0r) (unit: V = J C-1; positive for +Q, negative for −Q) Work done moving charge Q through potential difference ΔV: ΔW = QΔV E related to V: E = −ΔV/Δr (E = negative gradient of V–r graph) ΔV between two points = area under E–r graph between those points

Equipotential surfaces are surfaces of equal potential. No work is done moving a charge along an equipotential. Field lines are always perpendicular to equipotentials.

Trajectory in a uniform field: a charged particle entering a uniform electric field at right angles (e.g. between parallel plates) follows a parabolic path analogous to projectile motion (constant force perpendicular to initial velocity).

Comparison with gravity: same inverse-square-law form; both use potential concept and equipotentials. Key difference: gravity is always attractive, but electric force can attract or repel. The gravitational force between subatomic particles is negligible compared to the electrostatic force between them.

Electric potential is positive near a positive charge and negative near a negative charge. The closer to the charge, the larger the magnitude of the potential. Equipotentials are closer together where the field is stronger.

Section 7 (part) - Capacitance and magnetic fields

7.4  Capacitance

A capacitor stores electric charge and energy. It consists of two conducting plates separated by an insulator (dielectric).

Capacitance: C = Q/V (unit: farads, F) Parallel plate capacitor: C = Aε0εr/d εr = relative permittivity (dielectric constant) of the insulating material A polar molecule in the dielectric rotates in the electric field, reducing the field between the plates and increasing capacitance. Energy stored (= area under Q–V graph): E = ½QV = ½CV² = Q²/(2C) Capacitors in series: 1/C = 1/C1 + 1/C2 + ... Capacitors in parallel: C = C1 + C2 + ...

Charge and discharge through a resistor:

Discharging: Q = Q0e−t/RC; V = V0e−t/RC; I = I0e−t/RC Charging: Q = Q0(1 − e−t/RC); V = V0(1 − e−t/RC) Time constant: τ = RC (time for Q to fall to 37% of initial value during discharge) Time to halve: T½ = 0.69RC Graphical analysis: Q–t graph (discharge): gradient at any point = −Q/(RC) = −I ln Q vs t graph: gradient = −1/RC (allows RC to be found from graphical data) Area under I–t graph = charge flowed

Required Practical 9: investigation of the charge and discharge of capacitors. Analysis should include log-linear plotting (ln Q vs t) leading to determination of the time constant RC.

Energy stored = area under Q–V graph = ½QV. On a discharge Q–t graph, the gradient gives current (I = −dQ/dt). Plotting ln Q against t gives a straight line of gradient −1/RC, which is the key experimental method for finding RC.

7.5.1 – 7.5.2  Magnetic flux density and force on charges

A magnetic field exerts a force on moving charges and current-carrying conductors. The force is always perpendicular to both the velocity/current and the field direction.

Force on current-carrying wire (perpendicular to field): F = BIl (B = magnetic flux density in T; definition of the tesla: 1 T = 1 N A-1 m-1) General case: F = BIl sinθ (θ = angle between wire and B) Direction: Fleming’s left-hand rule. Thumb = Force, Index = Field, Middle = Current. Force on moving charge (perpendicular to field): F = BQv (general: F = BQv sinθ) Direction for a positive charge: same as conventional current (LHR). Direction for a negative charge: opposite to positive charge at the same velocity.

Required Practical 10: investigate how the force on a wire varies with flux density, current, and length of wire using a top-pan balance.

A charged particle moving perpendicular to a uniform magnetic field follows a circular path (magnetic force = centripetal force):

BQv = mv²/r → r = mv/(BQ) Larger momentum → larger radius. Application cyclotron: charged particles are accelerated between two D-shaped electrodes (dees) by an alternating electric field; the magnetic field keeps them in a circular path. As KE increases, radius increases, giving a spiral outward path until the beam exits.

The magnetic force does no work on a moving charge (always perpendicular to velocity), so speed and KE do not change only direction. This is why charged particles move in circles, not spirals, in a uniform magnetic field.

7.5.3 – 7.5.6  Electromagnetic induction, AC and transformers

Magnetic flux (B normal to area A): Φ = BA (unit: Wb = T m²) Flux linkage: NΦ = BAN cosθ (N = turns; θ = angle between B and normal to coil) Faraday's law: ε = NΔΦ/Δt = Δ(NΦ)/Δt (magnitude of induced EMF = rate of change of flux linkage) Lenz's law: the induced EMF opposes the change in flux causing it. EMF induced in a coil rotating uniformly in a magnetic field: ε = BANω sin(ωt) [maximum EMF = BANω when coil is parallel to field]

Applications: a straight conductor moving through a magnetic field has an EMF induced across it (Faraday's law flux linkage of the circuit changes). Simple dynamos and generators use a rotating coil.

Required Practical 11: investigate the effect on magnetic flux linkage of varying the angle between a search coil and a magnetic field direction, using a search coil and oscilloscope.


Alternating current (AC): sinusoidal waveforms only.

Peak current: I0; Peak-to-peak current: 2I0 RMS current: Irms = I0/√2; RMS voltage: Vrms = V0/√2 Mean power: P = VrmsIrms = Irms²R = Vrms²/R UK mains: Vrms = 230 V → V0 = 230√2 ≈ 325 V (peak-to-peak ≈ 650 V)

An oscilloscope can be used as a DC and AC voltmeter, to measure time intervals and frequencies, and to display AC waveforms. Familiarity with the controls (timebase, Y-gain) is expected; knowledge of the internal structure is not required.


Transformers:

Transformer equation: Ns/Np = Vs/Vp Efficiency: η = IsVs / (IpVp) (ideal transformer: η = 1, so IpVp = IsVs) Power loss in transmission line (resistance R): Ploss = I²R High-voltage transmission reduces I, reducing I²R losses for the same power transmitted.

Causes of inefficiency in real transformers:

  • Eddy currents: induced currents circulate in the iron core, dissipating energy as heat. Reduced by using a laminated (layered) core.
  • Resistance of windings: current through wire heats it (I²R losses).
  • Hysteresis losses: energy needed to repeatedly magnetise and demagnetise the core.

Lenz's law is a consequence of energy conservation. Transmitting power at high voltage reduces current; since Ploss = I²R, even doubling the voltage quarters the resistive losses for the same power delivered.

Section 8 - Nuclear physics

8.1.1 – 8.1.2  Rutherford scattering and radioactive emissions

Rutherford's alpha scattering experiment (1909–1911): alpha particles fired at thin gold foil. Results showed most passed straight through (nucleus is mostly empty space), some deflected slightly, and a very small number deflected by more than 90° proving the nucleus is small, dense, and positively charged. This replaced Thomson's “plum pudding” model, in which positive charge was spread throughout the atom.

Understanding of nuclear structure has continued to evolve: from Rutherford's nuclear model, to Chadwick's discovery of the neutron (1932), to the current quark model of nucleons.


RadiationNatureRange in airStopped byIonisationHazard
Alpha (α)42He nucleus~5 cmPaper / skinStrongly ionisingVery dangerous if ingested/inhaled
Beta (β)Fast electron~1 m~3 mm AlModerately ionisingSkin burns; less hazardous internally than α
Gamma (γ)EM radiationUnlimitedMany cm PbWeakly ionisingPenetrates body; requires shielding

Applications of radiation:

Thickness gauging
β radiation used to monitor thickness of aluminium foil and paper during manufacture; γ used for steel. Absorption changes with thickness, giving a continuous feedback signal.
Medical uses
Radiotherapy (targeted γ to kill cancer cells); diagnostic imaging (e.g. PET scans using β+ emitters). Balance between risk of radiation exposure and benefit of treatment/diagnosis must be assessed.

Safe handling: keep sources at distance (use tongs), minimise exposure time, use appropriate shielding (α: paper; β: aluminium; γ: lead/concrete), store in lead-lined containers, use dosimeters.


Inverse-square law for γ radiation:

I = k / x² where I = intensity (W m-2), x = distance from source, k = constant. Intensity decreases with the square of distance from a point source. Background radiation must be measured and subtracted before applying this law.

Background radiation is radiation from natural and artificial sources present at all times. Sources include: cosmic rays, radon gas (from rocks/soil), building materials, food, medical X-rays, nuclear industry. It must be subtracted from measured count rates to find the count rate due to the source alone.

Required Practical 12: investigation of the inverse-square law for gamma radiation.

Alpha particles are most ionising because of their large charge (+2) and slow speed. Gamma is least ionising but most penetrating. A magnetic field deflects α and β in opposite directions (by Fleming's left-hand rule) but not γ (uncharged). Always subtract background count rate before calculations.

8.1.3 – 8.1.4  Radioactive decay and nuclear instability

Radioactive decay is a random and spontaneous process: it cannot be predicted when a particular nucleus will decay, and it is not affected by external conditions (temperature, pressure, chemical state). Each nucleus has a constant probability of decaying per unit time (λ, the decay constant).

Rate of decay: ΔN/Δt = −λN (N = number of undecayed nuclei) Decay law: N = N0e−λt Activity: A = λN; A = A0e−λt Half-life: T½ = ln 2 / λ = 0.693 / λ Unit of activity: becquerel (Bq) = 1 decay per second Number of nuclei from mass: N = (m / M) × NA where m = mass of sample, M = molar mass, NA = 6.02×1023 mol−1

The half-life is the average time for the number of undecayed nuclei (or the activity) to halve. It is constant for a given nuclide and independent of the initial amount. Half-life can be determined from a decay curve by reading off when the count rate halves, or from a ln A vs t graph (gradient = −λ, so T½ = ln2/λ). Modelling with constant decay probability (e.g. using dice or a computer simulation) demonstrates the random nature of decay.

Applications: radioactive dating (e.g. carbon-14 for organic materials, uranium-lead for rocks) uses known half-lives to estimate age. Long half-lives make certain nuclides a challenge for radioactive waste storage (must remain isolated for thousands of years).


Nuclear instability decay modes:

Alpha (α) decay
Emits 42He. A → A−4; Z → Z−2. Typical: heavy nuclei (Z > 82) with too many nucleons.
Beta-minus (β) decay
n → p + e + ν̄e. A unchanged; Z → Z+1. Typical: nuclei with too many neutrons (above the N–Z stability line).
Beta-plus (β+) decay
p → n + e+ + νe. A unchanged; Z → Z−1. Typical: nuclei with too many protons (below the N–Z line).
Electron capture
A proton absorbs an inner orbital electron: p + e → n + νe. A unchanged; Z → Z−1. Competes with β+ decay.

N–Z stability graph: stable nuclei lie on a “valley of stability”. For light nuclei (Z ≤ 20), N ≈ Z. For heavier nuclei, N > Z (extra neutrons needed). Nuclei above the line (β emitters) or below it (β+ emitters / electron capture) decay towards the stable valley.

Nuclear energy levels and γ emission: after α or β decay the daughter nucleus may be in an excited state. It de-excites by emitting a γ photon (no change in A or Z). Example: technetium-99m (Tc-99m) is a metastable excited state that emits only γ rays widely used in medical diagnosis (short half-life ~6 h, no α/β emission minimises patient dose).

On an A–t or N–t graph, the quantity falls by half in each successive half-life. From a ln A vs t graph: gradient = −λ, y-intercept = ln A0. Always subtract background before plotting decay data.

8.1.5 – 8.1.6  Nuclear radius, mass-energy and binding energy

Nuclear radius two experimental methods:

Closest approach (alpha scattering)
At closest approach, all KE of α converts to electrostatic PE: ½mv² = kQq/rmin (using Coulomb’s law). This gives an upper estimate of nuclear radius. Typical nuclear radii: 1–10 fm (10−15 m).
Electron diffraction
High-energy electrons are diffracted by the nucleus. The intensity–angle graph shows a central maximum and subsidiary maxima (like single-slit diffraction). The first minimum position gives the nuclear radius. More accurate than closest-approach estimate.
Nuclear radius formula (derived from experimental data): R = R0A1/3 (R0 ≈ 1.05 fm = 1.05×10-15 m; A = nucleon number) Nuclear density (approximately constant for all nuclei): ρ = mnucleon × A / V = mnucleon × A / (&frac43;πR3) = mnucleon / (&frac43;πR03) ≈ 1017 kg m-3 (R ∝ A1/3 → V ∝ A → density is independent of A: all nuclei have the same density)

E = mc² applies to all energy changes not just nuclear reactions. Any system that loses energy loses mass (though the mass change is undetectable in everyday reactions).

Mass defect: Δm = Zmp + (A−Z)mn − mnucleus Binding energy: EB = Δmc² (energy to completely separate nucleus into free nucleons) BE per nucleon = EB / A Energy units: 1 u = 931.5 MeV/c²; 1 MeV = 1.6×10-13 J; 1 eV = 1.6×10-19 J

Binding energy per nucleon graph: peaks around A = 56 (iron-56), the most stable nucleus. Fission (heavy nuclei, A > ~100, split into two medium-mass nuclei) and fusion (light nuclei combine) both move product nuclei towards the peak increasing BE/nucleon and releasing energy. Students should be able to identify fission and fusion regions on the graph.

The physics of nuclear energy allows society to use science to inform decision-making about energy policy, weighing benefits (low CO&sub2;, large energy output) against risks (waste, accident risk, proliferation).

Binding energy is the energy RELEASED when a nucleus forms (or equivalently, the energy NEEDED to separate it). Higher BE/nucleon = more stable. In fission/fusion calculations, find the total mass before and after; Δm × c² = energy released.

8.1.7 – 8.1.8  Induced fission and safety

Induced fission: a slow (thermal) neutron is absorbed by a fissile nucleus (e.g. U-235), making it unstable. It splits into two daughter nuclei, releasing typically 2–3 fast neutrons and a large amount of energy.

Example: ²³⁵92U + ¹0n → ¹⁴¹56Ba + ⁹²36Kr + 3 ¹0n + energy

A chain reaction occurs when released neutrons cause further fissions. Critical mass is the minimum mass of fissile material needed to sustain a chain reaction (at least one neutron per fission causes another). In a reactor, control rods absorb excess neutrons to keep the reaction at the critical condition (exactly one neutron per fission continues the reaction).

Moderation (slowing neutrons): fast neutrons produced by fission must be slowed to thermal energies by a moderator. The mechanism is elastic collisions with moderator nuclei the neutron transfers more kinetic energy when it collides with a nucleus of similar mass (most efficient when masses are equal, e.g. hydrogen).

Moderator
Slows fast neutrons to thermal energies. Must be: light nuclei (efficient KE transfer), low neutron absorption. Materials: water (H2O), heavy water (D2O), graphite.
Control rods
Absorb neutrons to control reaction rate. Must be: high neutron absorption cross-section. Materials: boron steel, cadmium. Inserted further → slower reaction.
Coolant
Removes heat from reactor core to generate steam/electricity. Must be: thermally stable, low neutron absorption. Materials: water, CO2 gas, liquid sodium.

Safety aspects:

  • Fuel handling: uranium fuel rods handled remotely (high radioactivity)
  • Shielding: thick concrete and steel walls surround the reactor core
  • Emergency shut-down: control rods fully inserted to stop the chain reaction rapidly
  • Radioactive waste: spent fuel (high-level waste) is highly radioactive; stored in cooling ponds initially, then in sealed containers deep underground for long-term isolation

Appreciation of the balance between risks and benefits in the development of nuclear power: large energy output with low CO&sub2;; risks include accidents, long-lived waste, and proliferation concerns.


Nuclear fusion: two light nuclei combine to form a heavier nucleus. The product has a higher binding energy per nucleon than the reactants, so energy is released. Both fission (of heavy nuclei) and fusion (of light nuclei) move towards the peak of the BE/nucleon curve at iron-56.

Example (deuterium-tritium fusion): ²1H + ³1H → ⁴2He + ¹0n + 17.6 MeV Why fusion requires extreme conditions: • Nuclei are positively charged → strong electrostatic (Coulomb) repulsion at distance • Temperature ~10&sup8; K needed so that nuclei have enough thermal KE to overcome the Coulomb barrier and get close enough for the strong nuclear force to take over • High pressure (density) needed to increase collision rate sufficiently • These conditions occur naturally in the cores of stars (stellar nucleosynthesis)
Fusion in stars
Hydrogen nuclei fuse to form helium in stellar cores. Gravitational pressure and temperatures of ~10&sup7;–10&sup8; K provide the necessary conditions. Heavier elements are formed in more massive stars.
Fusion reactors (tokamaks)
Plasma of deuterium and tritium confined by magnetic fields at ~10&sup8; K. The challenge is sustaining plasma long enough to produce a net energy output. No commercial fusion reactor exists yet (JET, ITER projects ongoing).

In the reactor: the moderator slows neutrons; the control rods absorb neutrons; the coolant carries heat to the steam generator. Know which component does which function. For fusion: high temperature overcomes Coulomb repulsion; high pressure ensures sufficient collision rate.